1/16x^2-1/8x=-1

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Solution for 1/16x^2-1/8x=-1 equation: 


x in (-oo:+oo)

(1/16)*x^2-((1/8)*x) = -1 // + 1

(1/16)*x^2-((1/8)*x)+1 = 0

(1/16)*x^2+(-1/8)*x+1 = 0

1/16*x^2-1/8*x+1 = 0

DELTA = (-1/8)^2-(1/16*1*4)

DELTA = -15/64

DELTA < 0

x belongs to the empty set

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